9.3.1.1 Advantages Of Fully Differential Amplifiers

Fully differential amplifiers have the following advantages:

• Input-coupling capacitors not required:
  • The fully differential amplifier allows the inputs to be biased at a voltage other than mid-supply. For example, if a codec has a mid-supply lower than the mid-supply of the TPA2005D1-Q1 device, the common-mode feedback circuit adjusts, and the TPA2005D1-Q1 outputs still is biased at mid-supply of the TPA2005D1-Q1 device. The inputs of the TPA2005D1-Q1 device can be biased from 0.5 V to V_DD – 0.8 V. If the inputs are biased outside of that range, input-coupling capacitors are required.
• Mid-supply bypass capacitor, C_(BYPASS), not required:
  • The fully differential amplifier does not require a bypass capacitor. This is because any shift in the mid-supply affects both positive and negative channels equally and cancels at the differential output.
• Better RF immunity:
  • The fully differential amplifier cancels noise from RF interference much better than the typical audio amplifier.

9.3.3.1 Effect On Audio

The class-D amplifier outputs a pulse-width modulated (PWM) square wave, which is the sum of the switching waveform and the amplified input audio signal. The human ear acts as a band-pass filter such that only the frequencies between approximately 20 Hz and 20 kHz are passed. The switching frequency components are much greater than 20 kHz, so the only signal heard is the amplified input audio signal.

9.3.3.2 Traditional Class-D Modulation Scheme

The traditional class-D modulation scheme has a differential output in which each output is 180 degrees out of phase and changes from ground to the supply voltage, V_DD. Therefore, the differential pre-filtered output varies between positive and negative V_DD, where filtered 50% duty cycle yields 0 V across the load. The traditional class-D modulation scheme with voltage and current waveforms is shown in Figure 31. Note that, even at an average of 0 V across the load (50% duty cycle), the current to the load is high, causing a high loss and thus causing a high supply current.

Figure 31. Traditional Class-D Modulation Scheme Output Voltage and Current Waveforms Into an Inductive Load With No Input

9.3.3.3 TPA2005D1-Q1 Modulation Scheme

The TPA2005D1-Q1 device uses a modulation scheme that still has each output switching from 0 to the supply voltage. However, OUT+ and OUT– are now in phase with each other, with no input. The duty cycle of OUT+ is greater than 50% and OUT– is less than 50% for positive voltages. The duty cycle of OUT+ is less than 50% and OUT– is greater than 50% for negative voltages. The voltage across the load remains at 0 V throughout most of the switching period, greatly reducing the switching current, which reduces any I²R losses in the load.

Figure 32. TPA2005D1-Q1 Output Voltage and Current Waveforms Into an Inductive Load

9.3.3.4 Efficiency: Why You Must Use a Filter With The Traditional Class-D Modulation Scheme

The main reason that the traditional class-D amplifier needs an output filter is that the switching waveform results in maximum current flow. This causes more loss in the load, which causes lower efficiency. The ripple current is large for the traditional modulation scheme because the ripple current is proportional to voltage multiplied by the time at that voltage. The differential voltage swing is 2 × V_DD, and the time at each voltage is one-half the period for the traditional modulation scheme. An ideal LC filter is needed to store the ripple current from each half-cycle for the next half-cycle, while any resistance causes power dissipation. The speaker is both resistive and reactive, whereas an LC filter is almost purely reactive.

The TPA2005D1-Q1 modulation scheme has very little loss in the load without a filter because the pulses are very short and the change in voltage is V_DD instead of 2 × V_DD. As the output power increases, the pulses widen, making the ripple current larger. Ripple current could be filtered with an LC filter for increased efficiency, but for most applications the filter is not needed.

An LC filter with a cutoff frequency less than the class-D switching frequency allows the switching current to flow through the filter instead of the load. The filter has less resistance than the speaker, resulting in less power dissipation, which increases efficiency.

9.3.3.5 Effects Of Applying a Square Wave Into a Speaker

If the amplitude of a square wave is high enough and the frequency of the square wave is within the bandwidth of the speaker, a square wave could cause the voice coil to jump out of the air gap, scar the voice coil, or both. A 250-kHz switching frequency, however, is not significant because the speaker cone movement is proportional to 1/f² for frequencies beyond the audio band. Therefore, the amount of cone movement at the switching frequency is very small. However, damage could occur to the speaker if the voice coil is not designed to handle the additional power. To size the speaker for added power, the ripple current dissipated in the load must be calculated by subtracting the theoretical supplied power, P_{SUP THEORETICAL}, from the actual supply power, P_SUP, at maximum output power, P_OUT. The switching power dissipated in the speaker is the inverse of the measured efficiency, η_MEASURED, minus the theoretical efficiency, η_THEORETICAL.

Equation 2.

Equation 3.

Equation 4.

Equation 5.

The maximum efficiency of the TPA2005D1-Q1 device with a 3.6-V supply and an 8-Ω load is 86% from Equation 5. Using Equation 4 with the efficiency at maximum power (84%). An additional 17 mW is dissipated in the speaker. The added power dissipated in the speaker is not an issue as long as it is taken into account when choosing the speaker.

9.3.3.6 When to Use an Output Filter

Design the TPA2005D1-Q1 device without an output filter if the traces from amplifier to speaker are short. The TPA2005D1-Q1device passed FCC and CE radiated emissions with no shielding and with speaker trace wires 100 mm long or less.

A ferrite bead filter often can be used if the design is failing radiated emissions without an LC filter, and the frequency-sensitive circuit is greater than 1 MHz. If choosing a ferrite bead, choose one with high impedance at high frequencies, but very low impedance at low frequencies.

Use an LC output filter if there are low-frequency (<1 MHz) EMI-sensitive circuits and/or there are long leads from amplifier to speaker.

Figure 33 and Figure 34 show typical ferrite bead and LC output filters.

Figure 33. Typical Ferrite Chip Bead Filter (Chip Bead Example: NEC/Tokin: N2012ZPS121)

Figure 34. Typical LC Output Filter, Cutoff Frequency of 27 kHz

9.4.1.1 Summing Two Differential Input Signals

Two extra resistors are required for summing differential signals (a total of 5 components). The gain for each input source can be set independently (see Equation 6 and Equation 7 and Figure 35).

Equation 6.

Equation 7.

If summing left and right inputs with a gain of 1 V/V, use R_I1= R_I2= 300 kΩ.

Figure 35. Application Schematic With TPA2005D1-Q1 Summing Two Differential Inputs

9.4.1.2 Summing A Differential Input Signal And A Single-Ended Input Signal

Figure 36 shows how to sum a differential input signal and a single-ended input signal. Ground noise can couple in through IN+ with this method. It is better to use differential inputs. The corner frequency of the single-ended input is set by C_I2, shown in Equation 10. To ensure that each input is balanced, the single-ended input must be driven by a low-impedance source even if the input is not in use.

Equation 8.

Equation 9.

Equation 10.

The high-pass corner frequency of the single-ended input is set by C_I2. If the desired corner frequency is less than 20 Hz, then:

Equation 11.

Equation 12.

Figure 36. Application Schematic With TPA2005D1-Q1 Summing Differential Input And
Single-Ended Input Signals

9.4.1.3 Summing Two Single-Ended Input Signals

Four resistors and three capacitors are needed for summing single-ended input signals. The gain and corner frequencies (f_c1 and f_c2) for each input source can be set independently (see Equation 13 through Equation 16 and Figure 37). Resistor, R_P, and capacitor, C_P, are needed on the IN+ terminal to match the impedance on the IN– terminal. The single-ended inputs must be driven by low-impedance sources, even if one of the inputs is not outputting an AC signal.

Equation 13.

Equation 14.

Equation 15.

Equation 16.

Equation 17.

Equation 18.

Figure 37. Application Schematic With TPA2005D1-Q1 Summing Two Single-Ended Inputs