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INA326 ECG design questions and problems

Other Parts Discussed in Thread: INA326, OPA333, OPA335, OPA336, OPA348, OPA365, OPA340, OPA364

Dear all

I am a student working on ECG amplifier design.  Basically, I followed the design and suggestions from the a paper (see below link) with modifications using INA326 and OPA333/2333. In addition, I have read through the subject of <<INA326 EMG amplifier>> in this forum.

 

I have built a testing board and done measurements. I am facing two problems at this stage:

1. I used OPA333 to implement an activate electrode amplifier, which is actually a emitter follower without biasing, see the paper. I found its input impedance is not high enough, which is about 10Mohm. I expect it should higher than 1G ohm. My questions are

http://e2e.ti.com/cfs-file.ashx/__key/CommunityServer.Discussions.Components.Files/14/8551.Fabric_2D00_Based-Active-Electrode-Design-and.pdf

1.1 What is the input impedance of OPA333 with emitter follower configuration? I could not find it from the datasheet. 

1.2 Any suggestions to make its input impedance higher or I have to change another amplifier?

 

2. This question is about Driven Right Leg (DRL). I found that the DC level of DRL signal, see below, from INA326 is not exactly 1/2V+. This makes the DRL circuit to be saturated. Do you guys have any solution for improvement or avoid this.

 

Thank you very much!

 

Xijun

  • Xijun,

    I will do my best to provide some answers to your questions. 

    (1)  The typical bias current is +/-100pA which means under normal operating conditions the input impedance is much higher than 10M ohms, i.e. more on the order of G ohm range.  The OPA333 is an auto zero amplifier that uses a switched capacitor method to essentially zero out the input voltage offset.  If the OPA335 is driven into saturation, however, the virtual short at the inputs is lost and the potential across the inputs can increase, bias the internal substrate diodes, and draw much higher current than the nominal IB making the input impedance appear much lower.

    If the circuit in general is saturated, there may be several reasons for this.  I would first remove the RL drive and pull the inputs up through 2 10M ohm resistors to V+/2 to make sure the INA326 and the inputs are biased correctly.  If this is the case, it is possible that your saturation problem is a result of the RL drive.

    (2)  If the bias is not exactly 1/2V+, it could be a loop stability issue and/or a saturation issue as I mentioned earlier.  If you do not need the DC accuracy of the RL drive, you should consider replacing the OPA335 with another non-chopper OPA such as an OPA348 or an OPA336.

    I hope this helps.

    Matt

  • Hi Matt

     

    I appreciate your help and quick response.

     

    I would like to look into problem 1 (input impedance issue) first. For the circuit, please refer to the fig. 18 in OPA333 datasheet. (I have difficulty to paste diagrams here)

    The supple voltage is 3V DC. Input resistor, 5Kohm, was replaced by 10Mohm for measuring input resistance or input current

     

    I did some measurements this morning. I fed in a DC voltage to Vin. Then, I got:

    Vin (VDC)

    Vout (VDC)

    V- (VDC)

    V+ (VDC)

    I+ (uADC)

    0.5

    0.5

    0.5

    0.373

    0.013

    1

    1

    1

    0.553

    0.045

    1.5

    1.5

    1.5

    0.82

    0.068

    2

    2

    2

    1.082

    0.092

    2.5

    2.5

    2.5

    1.342

    0.116

    The input current of V+ is unexpectedly high. As the circuit is very sample, I cannot figure out where the problem is. 

    Do you have any suggestions for me? Besides, I would like change another Opamp for testing. What do you recommendation for Op-amps ?

     

    Thank you very much!

    Xijun

  • Xijun,

    The OPA333 requires a minimum supply difference of 1.8V.  Also, it does not make sense to me that you would be able to input a voltage of 1V to a buffer whose positive supply is  only .553V as the amplifier would saturate before hitting your target output. Indeed, this is what I believe is happening; my suspicion is if you move your V+ supply up to 2.5V your results will improve for all cases except the Vin = 2.5V case.

    Some other good amplifiers to consider that are low power are the OPA336 and the OPA348.

     

    Matt

  • Hi Matt

     

    Thank you very much for your quick reply again.

     

    I am sorry that if I made you confused about the test procedures and results.

     

    Below is the details of the test setup and results:

     

    Setup:

    ===============================================

    1.      Supply voltage: 3VDC

    2.      Test circuit: see below (replace 5Kohm resistor by 10Mohm for measurement)

    3.      Vin was connected to a DC power supply

    Test results:

    =======================================================

    Measurement results
    Vin (VDC) Vout (VDC) Voltage measured at the inverted input (-IN) of OPA333 (VDC) Voltage measured at the non-inverting input (+IN) of OPA333 (VDC) Calculated input current at +IN (uADC)
    0.5 0.5 0.5 0.373 0.013
    1 1 1 0.553 0.045
    1.5 1.5 1.5 0.82 0.068
    2 2 2 1.082 0.092
    2.5 2.5 2.5 1.342 0.116

     

     

    From the above test results, it did not seem that the op-amp was saturated because I could get expected voltage Vout, which was equal to Vin. However,

    1. the input current at +IN input was expectedly high.

    2. Voltage at -IN and +IN were not the same. (I though they should have very close)

     

    I do not have solid Op-amp design experience. I would appreciate it if you could point out where the problems are or give me some suggestions.

     

    By the way, I am going to test OPA336 once the samples arrive.

     

     

    Thank you very much!

     

    Xijun

     

     

  • Xijun,

    Something does not seem right.  The voltages at the inverting an d non-inverting terminals should be the same.  I would remove everything (including the resistor) and see if you can get the OPA333 to behave the way that a buffer should.

     

     

  • Hi Matt

     

    I agreed with you -- something does not seem right.

     

    I have just done a quick test you suggested -- removing the non-inverting input resistor. Below is the test results: 

     

     


    Vin (VDC) Vout (VDC) Voltage measured at inverted input (-IN) of OPA333 (VDC) Voltage measured at non-inverting input (+IN) of OPA333 (VDC) Input current at +IN (uADC)
    2.507 2.507 2.507 2.507 ~0.1

     

     

    The results looked good except the input current at +IN input. I used a current meter to measure the DC input current at the non-inverting input. It was about ~0.1uA. This result matches my previous test result with 10Mohm input resistor.

     

    Do you have any comments? I expect 100pA bias current.

     

    Xijun

     

     

     

  • Xijun,

    It is possible that the problem you were experiencing previously could have something to do with the shunt impedance of the volt meter if  you were measuring with respect to ground.  Keep in mind that the input bias current on an OPA such as the OPA333 which is an auto zero is a switched average of the voltage off the inputs; if you add anything to the circuit which perturbs this average it is possible that the bias current measurement can go awry.

    My guess is that  you are not measuring bias current correctly with the meter you are using.  Typically bias current is measured using an integration capacitor over a specified time period.  You can figure out what capacitor you need for this using i = C*dV/dt, so if you expect 100pA, you can easily see a 100mV change in 10 seconds which equates to a 100pA/100mV/10 = 1nF measurement capacitor.  The capacitors that are best for this type of measurement are polypropylene or polystyrene as they have very low leakages associated with them.

  • Hi Matt

     

    I really appreciate your quick response and I have to say 'thank you' again.

     

    I am not sure if I completely understand what I explained. Just two more questions:

    1. Is it okay to use a current meter, which is in series with +IN, for input bias current, measurement?

    2. If I use OPA336, will I face the similar problem as OPA333 for measuring bias current?

     

    Thanks!

     

    Xijun

  • Xijun,

    What is the exact model of the current meter you are using and what are its ranges?

     

    Matt

  • Hi Matt

     

    It is Fluke 83. I set it to uA range. I think this can measure current down to 0.1uA.

    If I put a volt meter in parallel to +IN, the bias current will go up from 0.1uA to 0.3uA. This means that the volt-meter take 2uA. 

     

    Xijun

  • Xijun,

     

    A fluke 83 is not sufficient in terms of accuracy or precision to measure pA of bias current.  I'm sure it will measure something, but not what you think.  Why are you trying to measure the bias current on the OPA333?  This is guaranteed in the data sheet...do you need it for some other purpose?

     

     

  • Hi Matt

     

    I would like to use OPA333 to make activate electrodes, which need very high input impedance. I expect it is in the order of Gohm. I just wanted to verify the input impedance of the prototype I made to make sure everything works well. It does not mean that I do not trust the datasheet.

    By the way, do you think OPA336 is better than OPA333 for my application because OPA336 takes 10pA bias current? What I exactly need is a single supple Op-amp with very high input impedance.

    Anyway, thank you very much for help. I will stop here for this question.

     

    Xijun

  • Xijun,

    The OPA336 has an effectively higher input impedance than the OPA333.  There are other amplifiers such as the OPA340, OPA364, and OPA365 which could also work for your application but are higher in quiescent power.

     

    Matt

  • Hi Matt

     

    Many thanks! I will switch to OPA336.

     

    Xijun

  • Hi Matt

     

    Please refer to the following reference circuit you provided. Is the value of R1 Int  (316Kohm) for the integrator U1 important? It is unlikely to find resistors with the exact value. I am going to use 330Kohm. Is it okay? Thanks!

     

    Xijun

  • Xijun,

    The RC in the integrator feedback sets the high pass filter value.  You can set this RC to whatever you would like--330k should be just fine.

    Matt

  • Hi Matt

     

    Regarding question 2: 

    "2. This question is about Driven Right Leg (DRL). I found that the DC level of DRL signal, see below, from INA326 is not exactly 1/2V+. This makes the DRL circuit to be saturated. Do you guys have any solution for improvement or avoid this."

    Questions:

    1. Can I use a capacitor with a large value, say 10uF, in between U4 and U5, to block the DC so that U4 will be be saturated? I have tried it and it looked good. Will this make the DRL circuit have no 60Hz cancellation?

    2. How can I fine tune the the DRL circuit to make it has the best cancellation effect? I think I need to adjust the gain of U4 to achieve maximum cancellation.

     

    Thank you very much

    Xijun

     

     

     

  • sir plz attach the tina schematic of above post plz

     

     

    thanks and regards

    harmanpreet

  • SIR PLZ MAIL ME THE TINA FILE OR POST IT FOR THIS SCHEMATIC

  • SIR PLZ ATTACH THE TINA SCHEMATIC FILE THIS IMAGE

  • HELLO ,SIR PLZ  ATTACH THE TINA  SCHEMATIC FILE FOR THIS PROBLEM

  • See attached.  Eliminating the half supply pedestal and adding the 10M resistor to ground off the output of U4 helps with convergence.

    Matt

    INA326_ECG_MH2.TSC
  • Hi Xijun

                      I am working with the desgining of a non contact ECG sensor for my project. Do u have any recommandations to me based on your experiance? How did you deal with the desigining of active electrode? Thanks