TIDUES0F June 2019 – April 2026 TMS320F28P550SG , TMS320F28P550SJ , TMS320F28P559SG-Q1 , TMS320F28P559SJ-Q1
The output capacitor in the dual-active bridge must be designed to handle the ripple. Figure 2-19 illustrates that the capacitor current is the difference between the current IHB2 and the output current ILoad, also called Iout as shown in Equation 17. The waveforms are also shown in Figure 2-20. IHB2 is the rectified and scaled inductor current. The best output current Iout is obtained by Pout / V2. From the difference between Iout and IHB2 the charge ΔQ (marked in blue) can be obtained. Afterward, the required capacitance can be calculated using Equation 18 for a maximum allowed ripple voltage.
Since the current waveforms depend on input-to-output voltage ratio and phase shift, this analysis needs to be done for all corner cases.
A MATLAB® script is used to obtain ΔQ for different input-to-output voltage ratios. The script first interpolates the ideal capacitor current waveform shown in Figure 2-20 and subtracts Iout. The resulting waveform is the capacitor current IC,out. Next, the integral of IC,out is calculated. Subtracting min(∫IC,out) of max(∫IC,out) provides ΔQ. This results in ΔQ of 12 µC for 10kW output power and nominal input and output voltages. For lower output voltages, ΔQ increases to 50 µC. Using Equation 18 and a voltage ripple of 5V leads to a required output capacitance of 10µF. Similar calculation can be done for primary side capacitors. Since the currents on primary side are lower, less capacitance is needed. The capacitors need to handle the ripple current at switching frequency, therefore low ESR Film capacitors are selected. In this reference design a output capacitance of 60µF and a input capacitance of 30µF was selected.
Figure 2-19 Output Current in Dual-Active BridgeThe capacitor also needs to be able to handle the RMS current, which is calculated with Equation 19.
where