SLVUCQ4 july   2023 TPS631012

 

  1.   1
  2.   Description
  3.   Features
  4.   4
  5. 1Evaluation Module Overview
    1. 1.1 Introduction
    2. 1.2 Kit Contents
    3. 1.3 Specification
    4. 1.4 Device Information
  6. 2Hardware
    1. 2.1 Background
    2. 2.2 Setup
    3. 2.3 Input and Output Connectors, Test Points, and Headers Description
      1. 2.3.1 J1, Pin 1 and 2 – VIN
      2. 2.3.2 J1, Pin 3 and 4 – S+/S-
      3. 2.3.3 J1, Pin 5 and 6 – GND
      4. 2.3.4 J2, Pin 1 and 2 – VOUT
      5. 2.3.5 J2, Pin 3 and 4 – S+/S-
      6. 2.3.6 J2, Pin 5 and 6 – GND
      7. 2.3.7 Test Points
        1. 2.3.7.1 J4, J5
        2. 2.3.7.2 TP1, TP2
      8. 2.3.8 Header Information
        1. 2.3.8.1 J6– I2C
      9. 2.3.9 Jumper Information
        1. 2.3.9.1 JP1 – ENABLE
    4. 2.4 Setup
    5. 2.5 Modifications
      1. 2.5.1 IC U1 Operation
  7. 3Software
    1. 3.1 Software Setup
    2. 3.2 Interface Hardware Setup
    3. 3.3 User Interface Operation
      1. 3.3.1 Home Screen
      2. 3.3.2 Settings Screen
      3. 3.3.3 Register Map Screen
    4. 3.4 Register Map
      1. 3.4.1 Register CONTROL1 (Target Address: 0x2A; Register Address: 0x02; Default: 0x08)
      2. 3.4.2 Register VOUT (Target Address: 0x2A; Register Address: 0x03; Default: 0x5C)
      3. 3.4.3 Register CONTROL2 (Target Address: 0x2A; Register Address: 0x05; Default:0x45)
  8. 4Hardware Design Files
    1. 4.1 Schematic
    2. 4.2 Board Layout
    3. 4.3 Bill of Materials
  9. 5Additional Information
    1. 5.1 Trademarks

Register VOUT (Target Address: 0x2A; Register Address: 0x03; Default: 0x5C)

Table 4-3 shows the STATUS register.

Return to Section 3.4.

This register contains the device status. A read operation to this register clears the status bits. This register is volatile, so the register loses contents if the voltage on the VIN pin becomes less than the UVLO threshold or a low logic level is applied to the EN pin.

Table 3-3 Register VOUT Field Descriptions
BitFieldTypeResetDescription
7:0VOUT[7:0]R/W0X5C

These bits set the output voltage

Output voltage = 1.000 + (VOUT[7 :0] × 0.025) V when 0x00<=VOUT[7 :0]<=0xB4;

Output voltage = 5.5 V when 0xB5<=VOUT[7 :0]<=0xFF