SNVSB63A September 2018 – June 2021 LP8732-Q1
PRODUCTION DATA
The inductor current ripple can be calculated using Equation 1 and Equation 2:


Example using Equation 1 and Equation 2:
| VIN(max) = 5.5 V |
| VOUT = 1 V |
| η = 0.75 |
| fSW = 1.8 MHz |
| L = 0.38 µH |
| then D = 0.242 and ΔIL = 1.59 A |
Peak current is half of the current ripple. If ILIM_FWD_SET_OTP is 3 A, the minimum forward current limit would be 2.85 A when taking the –5% tolerance into account. In this case the difference between set peak current and maximum load current = 0.795 A + 0.15 A = 0.945 A.
Figure 8-3 Current Limit vs Maximum Output Current