Figure 3 illustrates the proposed low-cost re-rush current control method. There are two
differences compared to Figure 1. First, RT has moved from the AC side to the DC side. Second, a
metal-oxide semiconductor field-effect transistor (MOSFET), Q5, has
replaced the traditional mechanical relay. The reason to choose a solid-state relay
is that you need to rapidly turn the relay on and off, and a mechanical relay is too
slow for this purpose. Also, because the MOSFET cannot turn off the AC voltage, it
is put on the DC side. The inrush current limit works the same as the traditional
method. The first time that the input voltage is applied to the PSU, RT
will limit the inrush current. Once the inrush current passes, Q5 turns
on and RT is bypassed.
Figure 4 illustrates the proposed re-rush current control method. VAC is the
PFC input voltage, VOUT is the PFC output voltage, and IAC is
the input current. Q1 and Q2 are high-frequency switches that
work as either a PFC boost switch or a synchronous switch alternatively in each AC
half cycle. The AC line drops for a period of 10ms and then comes back at its peak
while the PFC operates at full load. This is the worst case for AC voltage
dropout.
This is the proposed re-rush current
control method:
- At t0: Upon detection
of an AC voltage drop, Q1 and Q2 turn off. You must also
turn off both the PFC voltage and current loops because if the voltage loop and
current loop keep running, their integrators will accumulate. When the AC
voltage comes back and PFC turns on, a large PWM duty cycle will then be
present, resulting in a large current spike that may damage the power
supply.
- Once the current loop is turned
off, reset it to 0 and clear its integrator history. If you do not clear the
integrator, when the AC voltage comes back and PFC turns on, PFC will turn on
with the same PWM duty cycle before the AC voltage drop, and it may not be the
appropriate duty cycle. For example, if the AC voltage dropout occurs at zero
crossing, the PWM duty cycle is almost 100%. If the AC voltage comes back at the
AC peak without a cleared current-loop integrator, an almost 100% duty cycle
will occur at the AC peak and generate a large current spike, which could damage
the power supply. For the voltage loop, once it turns off, freeze it to keep its
internal value. The voltage loop output represents the load and is used for
current loop-reference generation; therefore, you want to keep its value so that
the load does not change during AC dropout.
- At t1: The AC voltage
returns. Because VAC > VOUT, a generated re-rush
current will charge the bulk capacitor. Q1 and Q2 remain
off.
- At t2: The re-rush
current exceeds a programmable threshold and trips a relay Q5 turnoff
event. The re-rush current is then limited by RT when Q5
is off, and its magnitude rapidly drops. Relay Q5 only turns
off for a very short period of time (for example, 10µs), then turns on again.
Once Q5 turns on, the re-rush current rises again until it exceeds
the threshold. This process repeats until the re-rush current never exceeds the
limit again. Figure 5 shows the flow chart for this process.
- At t3: VAC
< VOUT. Now it is time to turn on PFC. Set the voltage loop
reference equal to the instantaneous VOUT value at t3,
then turn on the voltage loop. After that, gradually increase the voltage loop
reference until it reaches the normal setpoint. For the current loop, first
calculate a duty cycle D = (VOUT – VAC)/VOUT
and inject it into the current loop such that the current loop output starts
from the calculated D when the current loop is on. Then turn on the current
loop. Finally, turn on Q1 and Q2 to allow PFC normal
operation.
This process repeats until
VOUT exceeds VAC.