SNVSD10 November   2025 LM4060-Q1

PRODUCTION DATA  

  1.   1
  2. 1 Features
  3. 2 Applications
  4. 3 Description
  5. 4 Device Comparison Table
  6. 5 Pin Configuration and Functions
  7. 6 Specifications
    1. 6.1 Absolute Maximum Ratings
    2. 6.2 ESD Ratings
    3. 6.3 Recommended Operating Conditions
    4. 6.4 Thermal Information
    5. 6.5 Electrical Characteristics
    6. 6.6 Typical Characteristics
  8. 7 Parameter Measurement Information
    1. 7.1 Temperature Coefficient
    2. 7.2 Solder Heat Shift
  9. 8 Detailed Description
    1. 8.1 Overview
    2. 8.2 Functional Block Diagram
    3. 8.3 Feature Description
      1. 8.3.1 Input Current (IR)
    4. 8.4 Device Functional Modes
  10. 9 Application and Implementation
    1. 9.1 Application Information
    2. 9.2 Typical Application
      1. 9.2.1 Design: LM4060-Q1 Precision Power Supply and Voltage Reference
        1. 9.2.1.1 Design Requirements
        2. 9.2.1.2 Detailed Design Procedure
        3. 9.2.1.3 Application Curves
    3. 9.3 Power Supply Recommendations
      1. 9.3.1 Power Dissipation and Device Operation
    4. 9.4 Layout
      1. 9.4.1 Layout Guidelines
      2. 9.4.2 Layout Example
  11. 10Device and Documentation Support
    1. 10.1 Third-Party Products Disclaimer
    2. 10.2 Documentation Support
      1. 10.2.1 Related Documentation
    3. 10.3 Receiving Notification of Documentation Updates
    4. 10.4 Support Resources
    5. 10.5 Trademarks
    6. 10.6 Electrostatic Discharge Caution
    7. 10.7 Glossary
  12. 11Revision History
  13. 12Mechanical, Packaging, and Orderable Information

9.2.1.2 Detailed Design Procedure

RS sets the cathode current of the shunt reference and is calculated using Equation 2. The resistor RS must be selected such that current IR remains in the operational region of the part for the entire VS range and load current range IL.

Equation 2. R S = V S - V R I L + I R

The two extremes to consider are VS at the minimum, and the load at the maximum, where RS must be small enough for IR to remain above IRMIN. For this design, design IR with a small margin of current for a total of 0.1mA. This design makes the maximum RS required to maintain operation at the worst case conditions to be 74Ω.

Equation 3. R SMAX = V SMIN - V R I LMAX + I R = 4 . 8 V - 3 . 3 V 20 mA + 0 . 15 mA + 0 . 1 mA = 74 Ω

The other extreme is VS at the maximum, and the load at the minimum, where RS must be large enough to maintain IR < IRMAX. For this design, the assumption is that the load is off. The calculated IRMAX is 25.6mA, which is less than the maximum the device can support.

Equation 4. I RMAX = V SMAX - V R R S - I LMIN = 5 . 2 V - 3 . 3 V 74 Ω = 25 . 6 mA

The same equation above is used to find out the typical current the device sinks.

Equation 5. I R = V S - V R R S - I L = 5 V - 3 . 3 V 74 Ω - 12 mA - 0 . 13 mA = 10 . 8 mA